User:76561198132370687/sandbox: Difference between revisions

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[math]\displaystyle{ P_r = \frac{\left(\frac{P_t G\sigma A}{4\pi d^2}\right)G}{4\pi d^2} = \frac{P_tG^2 \sigma A}{16\pi^2 d^4} }[/math]

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	<math>P_r = \frac{\left(\frac{P_t G\sigma A}{4\pi d^2}\right)G}{4\pi d^2} = \frac{P_tG^2 \sigma A}{16\pi^2 d^4}</math>		<math>P_r = \frac{\left(\frac{P_t G\sigma A}{4\pi d^2}\right)G}{4\pi d^2} = \frac{P_tG^2 \sigma A}{16\pi^2 d^4}</math>